sydneelittle3851 sydneelittle3851
  • 02-07-2018
  • Mathematics
contestada

Let the random variable x be equally likely to assume any of the values 1/12, 1/6, or 1/4. determine the mean and variance of x.

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 02-07-2018
The mean of x is
  (1/3)(1/12 + 1/6 + 1/4) = 1/6

The mean of the squares is
  (1/3)((1/12)² + (1/6)² + (1/4)²) = 7/216

The variance is the difference between the mean square and the square of the mean.
  7/216 -(1/6)² = 1/216

The mean of x is 1/6.
The variance of x is 1/216.
Answer Link

Otras preguntas

What's -25+86-873=? Equal????
how do u write a ratio in simplest form for 42/28
__________ attached to the rough endoplasmic reticulum produce secretory proteins.
a 26-mile section of a highway is designated as a scenic byway. New signs will be placed at the beginning and end of this section and at every 0.5 mile in betwe
what was a motivator for spanish explorations of north america
People living in equatorial countries have a darker skin tone than others. What would be the reason for this change in skin tone? A. The ancestors of the people
(8 - 20 divided by 2) Explain.
why strong Army need for any country?
how was the rosetta stone used
what is the expression for "the difference between four times a number and three times that number"?