Two chords AC and BD are intersecting inside the circle. The Intersecting Chord Theorem states that when two chords intersect inside a circle, the products of their segments are equal.
Thus, for the given circle: (AE) × (EC) = (BE) × (ED)
The lengths of the segments are AE = 7 EC = 2 BE = 4 ED = ?
To solve for ED, we simply substitute the known values into the equation [tex]ED = \frac{7(2)}{4} = \frac{14}{4} = 3.5[/tex]
