praolg
praolg
04-01-2017
Mathematics
contestada
rozwiąż równanie kwadratowe: 3/4 y^2 +9=y/2+(y-3)^2
Respuesta :
LammettHash
LammettHash
04-01-2017
Najpierw rozszerz po prawej strony równania.
[tex]\dfrac34y^2+9=\dfrac y2+(y-3)^2\implies\dfrac34y^2+9=\dfrac y2+y^2-6y+9[/tex]
Przenieść wszystko na jedną stronę i uproszcz.
[tex]\dfrac{y^2}4-\dfrac{11y}2=0[/tex]
Rozkładaj lewą stronę na czynniki.
[tex]\dfrac14y(y-22)=0[/tex]
Są dwa rozwiązania,
[tex]y=0\text{ i }y=22[/tex]
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