Respuesta :

kayt91

[tex] y - y1 = m(x - x1) [/tex]

[tex] y - (-1) = \frac{4}{3} (x - 9) [/tex]

[tex] y + 1 = \frac{4x - 36}{3} [/tex]

[tex] y + 1 = \frac{4x}{3} - 12 [/tex]

[tex] y = \frac{4x}{3} - 13 [/tex]

iloveonedirection
[tex](y-y_{1} )=m(x-x_{1})[/tex]

[tex]m= \frac{4}{3} [/tex]

[tex]y_{1}=-1[/tex]

[tex]x_{1} = 9[/tex]

[tex](y-(-1) )= \frac{4}{3} (x-(9))[/tex]

[tex](y+1)= \frac{4}{3} (x-9)[/tex]